Question

Resolver as equações: (deixe seus cálculos) a) a² - 8.a = 0 b) 3x² + 24x = 0 c) x² - 144 = 0 d) 4x² - 100 = alguém judas aí pfvr​

Answer 1

Resposta:

$a) \: {a}^{2} - 8 \times a = 0 \\ a(a - 8) = 0 \\ a = 0 \\ \\ a - 8 = 0 \\ a = 8$

b)

${3x}^{2} + 24x = 0 \\ x(3x + 24) = 0 \\ x = 0 \\ \\ 3x + 24 = 0 \\ 3x = - 24 \\ x = \frac{ - 24}{3} \\ x = - 8$

c)

${x}^{2} - 144 = 0 \\ {x}^{2} = 144 \\ x = \frac{ + }{} \sqrt{144} \\ x = \frac{ + }{} 12$

d)

$4 {x}^{2} - 100 = 0 \\ {4x}^{2} = 100 \\ {x}^{2} = \frac{100}{4} \\ {x}^{2} = 25 \\ x = \frac{ + }{} \sqrt{25} \\ x = \frac{ + }{} 5$

Explicação passo-a-passo:

Espero ter ajudado.

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{a^2 - 8a = 0}$

$\mathsf{a(a - 8) = 0}$

$\mathsf{a - 8 = 0}$

$\mathsf{a = 8}$

$\boxed{\boxed{\mathsf{S = \{0;8\}}}}$

$\mathsf{3x^2 + 24x = 0}$

$\mathsf{x(3x + 24) = 0}$

$\mathsf{3x + 24 = 0}$

$\mathsf{3x = -24}$

$\mathsf{x = -8}$

$\boxed{\boxed{\mathsf{S = \{0;-8\}}}}$

$\mathsf{x^2 - 144 = 0}$

$\mathsf{x^2 = 144}$

$\mathsf{x = \pm\:\sqrt{144}}$

$\mathsf{x = \pm\:12}$

$\boxed{\boxed{\mathsf{S = \{12;-12\}}}}$

$\mathsf{4x^2 - 100 = 0}$

$\mathsf{4x^2 = 100}$

$\mathsf{x^2 = 25}$

$\mathsf{x = \pm\:\sqrt{25}}$

$\mathsf{x = \pm\:5}$

$\boxed{\boxed{\mathsf{S = \{5;-5\}}}}$