Question

ph e poh de 0,01 mol por litro de HCL

Answer 1

[H+] = 0,01 mol/L = 10^-2 mol/L


pH = -log[H+]
pH = - log[10^-2]
pH = -( -2*log10)
pH = 2

pH + pOH = 14
2 + pOH = 14
pOH = 12

Resposta: pH = 2 e pOH = 12.