Question

sabendo que a=3/5 e b=1/3 qual o valor da expressao (a-b)2÷(a+b)2.

Answer 1

Resposta:

Eu acho que é assim

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{a = \dfrac{3}{5},\:b = \dfrac{1}{3}}$

$\mathsf{\dfrac{(a - b)^2}{(a + b)^2} = \dfrac{\left[\left(\dfrac{3}{5}\right) - \left(\dfrac{1}{3}\right)\right]^2}{\left[\left(\dfrac{3}{5}\right) + \left(\dfrac{1}{3}\right)\right]^2}}$

$\mathsf{\dfrac{(a - b)^2}{(a + b)^2} = \dfrac{\left[\left(\dfrac{9 - 5}{15}\right)\right]^2}{\left[\left(\dfrac{9 + 5}{15}\right)\right]^2}}$

$\mathsf{\dfrac{(a - b)^2}{(a + b)^2} = \dfrac{\left[\left(\dfrac{4}{15}\right)\right]^2}{\left[\left(\dfrac{14}{15}\right)\right]^2}}$

$\mathsf{\dfrac{(a - b)^2}{(a + b)^2} = \dfrac{\left(\dfrac{16}{225}\right)}{\left(\dfrac{196}{225}\right)}}$

$\mathsf{\dfrac{(a - b)^2}{(a + b)^2} = \dfrac{16}{196}}$

$\boxed{\boxed{\mathsf{\dfrac{(a - b)^2}{(a + b)^2} = \dfrac{4}{49}}}}$