Question

Seja a função definida por f(x) = x³ − 7. Então f(0) + f(−1) + f(1/2) é:

Answer 1

$f(x)=x^3-7$

$f(0)=0^3-7\\f(0)=0-7\\f(0)=-7$

$f(-1)=(-1)^3-7$

$f(-1)=-1-7$

$f(-1)=-8$

$f(\frac{1}{2})=(\frac{1}{2})^3-7$

$f(\frac{1}{2})=\frac{1}{8}-7$

$f(\frac{1}{2})=\frac{1}{8}-\frac{56}{8}$

$f(\frac{1}{2})=-\frac{55}{8}$

$f(0)+f(-1)+f(\frac{1}{2})=$

$-7+(-8)+(-\frac{55}{8})=$

$-7-8-\frac{55}{8}=$

$-\frac{56}{8} -\frac{64}{8} -\frac{55}{8}=$

$-\frac{175}{8}$