• Matéria: Matemática
  • Autor: dossantoslopesmariag
  • Perguntado 3 anos atrás

1)calcule pelo processo da decomposição simultânea o MMC de: a)12e15 c)6e20 12,15 6,20 b)30e48 30,48 e)e6e20 30, 6,20 MMC (12,15)= MMC (30,48)= MMC (0p6,20)= d) 60 e 24 e 45 e) 36 f )18 e 27 MMC (60,24)= MMC (36,45)= MMC (18,27)= 2) continue calculando :a) MMC (12, 20 , 40 = b) MMC ( 24 , 36 , 54 = 12 , 30 40
34 , 36 , 54 6, 15 , 20 c) MMC ( 18, 20, 45)= d) MMC ( 40 , 45, 72 )= ​

Me AJUDA!

Respostas

respondido por: paborakpal9c7
3

Resolvendo o que entendi, pois o seu enunciado ficou muito confuso...

a) MMC (12,15)= 60

12, 15 | 2

6, 15 | 2

3, 15 | 3

1, 5 | 5

1, 1 | 1

MMC = 2 . 2 . 3 . 5 = 60

b) MMC (30,48)= 240

30, 48 | 2

15, 24 | 2

15, 12 | 2

15, 6 | 2

15, 3 | 3

5, 1 | 5

1, 1 | 1

MMC = 2 . 2 . 2 . 2 . 3 . 5 = 240

c) MMC (6,20)= 60

6, 20 | 2

3, 10 | 2

3, 5 | 3

1, 5 | 5

1, 1 | 1

MMC = 2 . 2 . 3 . 5 = 60

d) MMC(60,24)= 120

60, 24 | 2

30, 12 | 2

15, 6 | 2

15, 3 | 3

5, 1 | 5

1, 1 | 1

MMC = 2 . 2 . 2 . 3 . 5 = 120

e) MMC (36,45)= 180

36, 45 | 2

18, 45 | 2

9, 45 | 3

3, 15 | 3

1, 5 | 5

1, 1 | 1

MMC = 2 . 2 . 3 . 3 . 5 = 180

f) MMC (18,27)= 54

18, 27 | 2

9, 27 | 3

3, 9 | 3

1, 3 | 3

1, 1 | 1

MMC = 2 . 3 . 3 . 3 = 54

2) continue calculando :

a) MMC (12, 20 , 40) = 120

12, 20, 40 | 2

6, 10, 20 | 2

3, 5, 10 | 2

3, 5, 5 | 3

1, 5, 5 | 5

1, 1, 1 | 1

MMC = 2 . 2 . 2 . 3 . 5 = 120

b) MMC ( 24 , 36 , 54) = 216

24, 36, 54 | 2

12, 18, 27 | 2

6, 9, 27 | 2

3, 9, 27 | 3

1, 3, 9 | 3

1, 1, 3 | 3

1, 1, 1 | 1

MMC = 2 . 2 . 2 . 3 . 3 . 3 = 216

c) MMC ( 18, 20, 45)= 180

18, 20, 45 | 2

9, 10, 45 | 2

9, 5, 45 | 3

3, 5, 15 | 3

1, 5, 5 | 5

1, 1, 1 | 1

MMC = 2 . 2 . 3 . 3 . 5 = 180

d) MMC ( 40 , 45, 72 )= ​360

40, 45, 72 | 2

20, 45, 36 | 2

10, 45, 18 | 2

5, 45, 9 | 3

5, 15, 3 | 3

5, 5, 1 | 5

1, 1, 1 | 1

MMC = 2 . 2 . 2 . 3 . 3 . 5 = 360


dossantoslopesmariag: obrigada
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