Question

A=2y+10<-3y-10
B= 7a-4a+3>9
C=10m-12<3m-12
D=6b+b<3b-15

Answer 1

$\Huge \sf A) \dfrac {} {}\\\Huge \sf 2y+10<-3y-10 \dfrac {} {}\\\Huge \sf 2y + 3y < -10 - 10 \dfrac {} {}\\\Huge \sf 5y< -20 \dfrac {} {}\\\Huge \sf y< \dfrac {-20} {5}\\\Huge \sf y<-4 \dfrac {} {}$

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$\Huge \sf B) \dfrac {} {}\\\Huge \sf 7a-4a+3>9 \dfrac {} {}\\\Huge \sf 7a - 4a> 9 - 3 \dfrac {} {}\\\Huge \sf 3a > 6 \dfrac {} {}\\\Huge \sf a > \dfrac {6} {3}\\\\ \sf a> 2 \dfrac {} {}$

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$\Huge \sf C) \dfrac {} {}\\\Huge \sf 10m-12<3m-12 \dfrac {} {}\\\Huge \sf 10 m - 3m < - 12 + 12 \dfrac {} {}\\\\\Huge \sf 7m < 0 \dfrac {} {}\\\\\Huge \sf m< \dfrac {0} {7}\\\\\Huge \sf m<0 \dfrac {} {}$

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$\Huge \sf D) \dfrac {} {}\\\Huge \sf 6b+b<3b-15 \dfrac {} {}\\\Huge \sf 6b + b - 3b < -15 \dfrac {} {}\\\Huge \sf 4b <-15 \dfrac {} {}\\\Huge \sf b< \dfrac {-15} {4}$