Question

x²+18x+16 = qual o resultado por favor, em detalhes

Answer 1

Boa tarde!


Solução!


$x^{2} +18x+16=0$


Vamos resolver a equação do segundo grau usando a formula de Bhaskara.


$a=1\\\\ b=18\\\\ c=16$



$x= \dfrac{-b\pm \sqrt{b^{2}-4.a.c } }{2.a} \\\\\\\ x= \dfrac{-18\pm \sqrt{18^{2}-4.1.16 } }{2.1} \\\\\\\ x= \dfrac{-18\pm \sqrt{324-64 } }{2} \\\\\\\ x= \dfrac{-18\pm \sqrt{260} }{2} \\\\\\\ x= \dfrac{-18\pm 2\sqrt{65} }{2} \\\\\\\ x= \dfrac{2(-9\pm \sqrt{65}) }{2} \\\\\\\ x=-9\pm \sqrt{65}$



$x_{1}=-9+ \sqrt{65} \\\\\\ x_{2}=-9- \sqrt{65} \\\\\\\\\\\ \boxed{Resposta:S=( -9+ \sqrt{65},-9- \sqrt{65} )}$



Boa tarde!
Bons estudos!