Question

1 – Resolva a inequação x² − 5x + 4 < 0. *

Answer 1

Resposta:

X

2

−5x+4=0 A=1 B= -5 C = 4

Pela fórmula de Bháskara:

\Delta=B^2-4.A.CΔ=B

2

−4.A.C

\Delta=(-5)^2-4.1.4Δ=(−5)

2

−4.1.4

\Delta=25-16Δ=25−16

\boxed{\Delta=9}

Δ=9

X=\frac{-B+-\sqrt{\Delta}}{2.A}X=

2.A

−B+−

Δ

X=\frac{5+-\sqrt{9}}{2.1}X=

2.1

5+−

9

X=\frac{5+-3}{2}X=

2

5+−3

X_{1}=\frac{5+3}{2}X

1

=

2

5+3

>>> X_{1}=\frac{8}{2}X

1

=

2

8

>>> \boxed{X_{1}=4}

X

1

=4

X_{2}=\frac{5-3}{2}X

2

=

2

5−3

>>> X_{2}=\frac{2}{2}X

2

=

2

2

>>> \boxed{X_{2}=1}

X

2

=1

\Large{\boxed{\boxed{S=\{\ 4,\ 1\ \}}}}

S={ 4, 1 }

espero que entenda!!