Question

dada a funcao afim f(x)=-2x+3 determine f(f(1/3))

Answer 1

f(x) = -2x + 3

f(1/3) = -2 . (1/3) + 3

f(1/3) = -2/3 + 3

f(1/3) = (-2 + 9) / 3

f(1/3) = 7/3

f(7/3) = -2 . (7/3) + 3

f(7/3) = -14/3 + 3

f(7/3) = (-14 + 9) / 3

f(7/3) = -5/3

Answer 2

f(x) = - 2x + 3

• f(1/3) = - 2 . 1/3 + 3

f(1/3) = - 2/3 + 3

f(1/3) = (- 2 + 9)/3

f(1/3) = 7/3

• f(7/3) = - 2 . 7/3 + 3

f(7/3) = - 14/3 + 3

f(7/3) = (- 14 + 9)/3

f(7/3) = - 5/3

att. yrz