Question

determine o 8 (oitavo) termo da pg (8,4,2,1,1/2,...)
por favor a conta

Answer 1

A resposta será igual a 1/16. :D

Answer 2

$q=\frac{1}{2}\\\ a_n=a_1*q^{n-1}\\\ a_8=8*( \frac{1}{2})^{8-1} \\\ a_8=8*( \frac{1}{2})^{7} \\\ a_8=8*( \frac{1}{2^7}) \\\ a_8=2^3*( \frac{1}{2^7}) \\\ a_8=( \frac{2^3}{2^7}) \\\ a_8=2^{3-7}\\\ a_8=2^{-4}\\\\ a_8=\frac{1}{2^4}\\\ a_8=\frac{1}{16}$