Question

Opá! Alguem pode mé ajudar com essas atividades!

ESTOU COM MUITA DÚVIDA ಠﭛಠ​

Answer 1

eu ja fiz isso calma ae vou ver aqui no caderno ok?

Answer 2

Resposta:

rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr$x^{2} \sqrt{x} \neq \geq \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \neq \lim_{n \to \infty} a_n$

Explicação: