Question

O valor de y na figura abaixo é: ( Considere V3 como sendo a raiz de 3 )

Answer 1

$\Large\boxed{\begin{array}{l}\sf tg(60^\circ)=\dfrac{x}{y}\\\sf \sqrt{3}=\dfrac{x}{y}\\\sf x=y\sqrt{3}\\\sf tg(45^\circ)=\dfrac{x}{50+y}\\\sf 1=\dfrac{y\sqrt{3}}{50+y}\\\sf y\sqrt{3}=50+y\\\sf y\sqrt{3}-y=50\\\sf y\cdot(\sqrt{3}-1)=50\\\\\huge\boxed{\boxed{\boxed{\boxed{\sf y=\dfrac{50}{\sqrt{3}-1}}}}}\end{array}}$