Question

Sendo log 10 elevado a 2= 0,301 e log 10 elevado a 3 = 0477, calcule:
a) Log 10 elevado a 5


b) Log 10 =
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8

Answer 1

Olá Dineia

log(2) = 0.301
log(3) = 0.477
log(10) = 1

a) 

log(5) = log(10/2) = log(10) - log(2) = 1 - 0.301 = 0.699 

b) 

log(10/8) = log(10) - log(8) = log(10) - log(2^3) 

log(10/8) = 1 - 3log(2) = 1 - 3*0.301 = 1 - 0.903 = 0.097