Question

Por favor,me ajudem!!!! é urgente!!!! ​

Answer 1

Resposta:

Explicação passo a passo:

$1)$

$a)\:F$

$b)\:V$

$c)\:V$

$d)\:V$

$2)$

$a)$

$4\sqrt{7}+8\sqrt{7}-2\sqrt[3]{5}+8\sqrt[3]{5}-3\sqrt[3]{5}=$

         $12\sqrt{7}+3\sqrt[3]{5}$

$b)$

$\sqrt[3]{375} +\sqrt[3]{81} -2\sqrt[3]{24}+\sqrt[3]{189} =$

$\sqrt[3]{3.5^{3} } +\sqrt[3]{3^{3}.3 } -2\sqrt[3]{2^{3}.3 } +\sqrt[3]{3^{3}.7 } =$

$5\sqrt[3]{3} +3\sqrt[3]{3}-4\sqrt[3]{3} \:+3\sqrt[3]{7} =$

$4\sqrt[3]{3} +3\sqrt[3]{7}$

$3)$

$a)$

$\frac{2}{\sqrt{6} } =\frac{2.\sqrt{6} }{\sqrt{6}.\sqrt{6} }=\frac{2\sqrt{6} }{\sqrt{36} }=\frac{2\sqrt{6} }{6} =\frac{\sqrt{6} }{3}$

$b)$

$\frac{3\sqrt{3} }{(2-\sqrt{3}) } =\frac{3\sqrt{3}.(2+\sqrt{3}) }{(2-\sqrt{3}).(2+\sqrt{3}) } =\frac{6\sqrt{3}+9}{2^{2}-(\sqrt{3}) ^{2} } =\frac{6\sqrt{3}+9 }{4-3} =6\sqrt{3} +9$