Question

Equação exponencial, segue a foto:

Answer 1

$( \frac{1}{3} )^{-x + 2}= \sqrt[4]{9} \\( \frac{1}{3} )^{-x + 2}= 9^{ \frac{1}{4}} \\ ( \frac{1}{3} )^{-x + 2}=(3^{2})^{ \frac{1}{4} } \\ ( \frac{1}{3} )^{-x + 2}=3^{ \frac{2}{4} } \\ ( \frac{1}{3} )^{-x + 2}=3^{ \frac{1}{2} } \\ ( \frac{1}{3})^{-x+2}= (\frac{1}{3})^{- \frac{1}{2} }} \\ -x + 2= -\frac{1}{2} \\ -2x + 4 = -1 \\ -2x = -1 - 4 \\ -2x = -5 \\ 2x = 5 \\ x = \frac{5}{2}$

Espero ter ajudado.