Question

A forma é de bascara

Answer 1

Resposta:

Olá bom dia!

Por Bháskara:

$x = \frac{-b^+_-\sqrt{delta} }{2a}$

delta = Δ = b² - 4ac

1)

a = 1 ; b = -5 ; c = 6

Δ = (-5)² - 4(1)(6)

Δ = 25 - 24

Δ = 1

√Δ = ±√1 = ±1

x = (5 ± 1) / (2*1)

x = (5 ± 1)/2

x' = (5 + 1)/2 = 6/2 = 3

x" = (5 - 1)/2 = 4/2 = 2

S = {2;3}

2)

a = 1 ; b = -7 ; c = 10

Δ = (-7)² - 4(1)(10)

Δ = 49 - 40

Δ = 9

√Δ = ±√9 = ±3

x = (7 ± 3) / (2*1)

x = (7 ± 3)/2

x' = (7 + 3)/2 = 10/2 = 5

x" = (7 - 3)/2 = 4/2 = 2

S = {2;5}

3)

a = 4 ; b = -4 ; c = 1

Δ = (-4)² - 4(4)(1)

Δ = 16 - 16

Δ = 0

√Δ = ±√0 = 0

x = (4 ± 0) / (2*4)

x = 4/8

x = 1/2

S = {1/2}

Answer 2

Resposta:

a) x² - 5x + 6 = 0

a = 1, b = -5, c = 6

Δ = 25 - 24 = 1

as raízes

x1 = (5 + 1)/2 = 3

x2 = (5 - 1)/2 = 2

S = (2, 3)

b) x² - 7x + 10 = 0

a = 1, b = -7, c = 10

Δ = 49 - 40 = 9

as raízes

x1 = (7 + 3)/2 = 5

x2 = (7 - 3)/2 = 2

S = (2, 5)

c) 4x² - 4x + 1 = 0

a = 1, b = -4, c = 1

Δ = 16 - 16 = 0

a raíz

x = 4/8 = 1/2

S = (1/2)