Question

determine o 14° termo da PG (1536,768,384,192...)

Answer 1

P.G(1536,768,384,192......)
a 1 = 1536 
a 2 = 768
q = a 2 / a 1
q = 768/1536
q =1/2
a 14 = a 1 .q ^n-1
a 14 = 1536 . (1/2)^14-1
a 14 = 1536 . (1/2) ^13
a 14 = 1536 . 1/8192
a 14 = 1536/8192
a 14 = 0,1875