Question

Resolva as divisões e as potencia dos monômios:

a) (-3abc) : (-ab) =

b) ( 75x³ – 45x² ) : 3x =

c) (30a³b²) : ( 15ab²) =

d) (–48abc) : (+8ac) =

e) (6x²y - 9y) : 3y =

f) (18x³yb + 24y²b - 30) : 6xyb=

g) ( - 2xy²)³ =

h) ( - 3xy²)² =

i) ( 4ab)³ =

j) ( - m²j)² =

Genteee me ajudem rapidoooo, por favorrr é urgenteee

Answer 1

Resposta:

A) $=3c$

B) $=5x\left(5x-3\right)$

C) $=2a^2$

D) $=-6b$

E) $=2x^2-3$

F) $=\frac{3bx^3y+4by^2-5}{bxy}$

G) $=-8x^3y^6$

H) $=9x^2y^4$

I) $=64a^3b^3$

J) $=m^4j^2$

Explicação passo a passo:

A) $\frac{-3abc}{-ab}$

$=\frac{3abc}{ab}$

$=\frac{3bc}{b}$

$=3c$

B) $\frac{75x^3-45x^2}{3x}$

$=\frac{15x^2\left(5x-3\right)}{3x}$

$=\frac{3\cdot \:5x^2\left(5x-3\right)}{3x}$

$=\frac{5x^2\left(5x-3\right)}{x}$

$=\frac{5xx\left(5x-3\right)}{x}$

$=5x\left(5x-3\right)$

C) $\frac{30a^3b^2}{15ab^2}$

$=\frac{30a^3}{15a}$

$=\frac{15\cdot \:2a^3}{15a}$

$=\frac{2a^3}{a}$

$=2a^2$

D) $\frac{-48abc}{8ac}$

$=\frac{-48bc}{8c}$

$=\frac{-48b}{8}$

$=-6b$

E) $\frac{6x^2y-9y}{3y}$

$=\frac{3y\left(2x^2-3\right)}{3y}$

$=\frac{y\left(2x^2-3\right)}{y}$

$=2x^2-3$

F) $\frac{18x^3yb+24y^2b-30}{6xyb}$

$=\frac{6\left(3x^3yb+4y^2b-5\right)}{6xyb}$

$=\frac{3bx^3y+4by^2-5}{bxy}$

G) $\left(-2xy^2\right)^3$

$=-\left(2xy^2\right)^3$

$=-2^3x^3\left(y^2\right)^3$

$=-8x^3\left(y^2\right)^3$

$=-8x^3y^6$

H) $\left(-3xy^2\right)^2$

$=\left(3xy^2\right)^2$

$=3^2x^2\left(y^2\right)^2$

$=9x^2\left(y^2\right)^2$

$=9x^2y^4$

I) $\left(4ab\right)^3$

$=4^3a^3b^3$

$=64a^3b^3$

J) $\left(-m^2j\right)^2$

$=\left(m^2j\right)^2$

$=\left(m^2\right)^2j^2$

$=m^4j^2$