Question

calcule o perimetrl do triangulo abc, sendo a(1,1) b (2,2)/e c (3,-1)

Answer 1

Sendo A(1,1) ; B(2,2) e C(3,1) fica:

dAB = √(xA-xB)² + (yA - yB)² = √ (1-2)² + (1-2)² = √2

dAC = 2√2

dBC = √10

Perímetro = √2 + 2√2 + √10

Perímetro = 3√2 + √10

Perímetro ≈ 7,40

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29/03/2016
Sepauto - SSRC
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