Question

ALGUEM ME AJUDA SO ATE 00.00 DE HOGE​

Answer 1

Resposta:

-1/12 e (0 e 1)

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Answer 2

Questão 5)

$2.2^{x} = \sqrt[6]{8} . \sqrt[4]{2} .\sqrt[6]{2} \\2^{x+1} = \sqrt[6]{2^{3} } . \sqrt[4]{2} .\sqrt[6]{2} \\2^{x+1} = 2^{3/6} . 2^{1/4} . 2^{1/6}\\2^{x+1} = 2^{(3/6) + (1/4) + (1/6)}\\x + 1 = 3/6 + 1/4 + 1/6\\x + 1 = 6/12 + 3/12 + 2/12\\x + 1 = 11/12\\x = 11/12 - 1\\x = -1/12$

Questão 6)

$9^{x} + 3 = 4 . 3^{x} \\3^{x} . ^{2} + 3 - 4 . 3^{x} = 0\\\\ 3^{x} = y\\\\y^{2} - 4y + 3 = 0\\\\y = 3 \\y = 1\\\\3^{x} = 1\\x = 0\\\\ 3^{x} = 3\\x = 1$

Resposta : x = 0 ou x = 3