Question

Calcule a altura do triângulo equilátero de área igual a 4 raiz de 3 cm.

Answer 1

$\Large\boxed{\begin{array}{l}\sf A=4\sqrt{3}\\\sf\dfrac{l^2\diagup\!\!\!\!\!\sqrt{3}}{4}=4\diagup\!\!\!\!\!\sqrt{3}\\\\\sf l^2=16\\\sf l=\sqrt{16}\\\sf l=4\\\sf h=\dfrac{l\sqrt{3}}{2}\\\\\sf h=\dfrac{4\sqrt{3}}{2}\\\\\sf h=2\sqrt{3}~cm\end{array}}$