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Boa noite Victao!
Solução!
Para determinar a razão de uma P,G basta dividir o termo posterior pelo anterior.
![q= \dfrac{a2}{a1} \\\\\\
a1= \sqrt{2} \\\\\
a2= \sqrt{6} \\\\\\\
q= \dfrac{ \sqrt{ 6 } }{ \sqrt{2 } } \\\\\\\
q= \dfrac{ \sqrt{6}. \sqrt{2} }{ \sqrt{2}. \sqrt{2}}\\\\\\\
q= \dfrac{ \sqrt{12} }{ \sqrt{4}}\\\\\\\
q= \dfrac{ 2\sqrt{3} }{2}\\\\\\\
q= \sqrt{3}](https://tex.z-dn.net/?f=q%3D+%5Cdfrac%7Ba2%7D%7Ba1%7D+%5C%5C%5C%5C%5C%5C%0Aa1%3D+%5Csqrt%7B2%7D+%5C%5C%5C%5C%5C%0Aa2%3D+%5Csqrt%7B6%7D+%5C%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B+%5Csqrt%7B+6+%7D+%7D%7B+%5Csqrt%7B2+%7D+%7D+%5C%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B+%5Csqrt%7B6%7D.+%5Csqrt%7B2%7D++%7D%7B+%5Csqrt%7B2%7D.+%5Csqrt%7B2%7D%7D%5C%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B+%5Csqrt%7B12%7D++%7D%7B+%5Csqrt%7B4%7D%7D%5C%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B+2%5Csqrt%7B3%7D++%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Csqrt%7B3%7D+%0A%0A%0A+ "q= \dfrac{a2}{a1} \\\\\\
a1= \sqrt{2} \\\\\
a2= \sqrt{6} \\\\\\\
q= \dfrac{ \sqrt{ 6 } }{ \sqrt{2 } } \\\\\\\
q= \dfrac{ \sqrt{6}. \sqrt{2} }{ \sqrt{2}. \sqrt{2}}\\\\\\\
q= \dfrac{ \sqrt{12} }{ \sqrt{4}}\\\\\\\
q= \dfrac{ 2\sqrt{3} }{2}\\\\\\\
q= \sqrt{3}")
Boa noite!
Bons estudos!
Solução!
Para determinar a razão de uma P,G basta dividir o termo posterior pelo anterior.
Boa noite!
Bons estudos!
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