• Matéria: Matemática
  • Autor: lailicaperoncita
  • Perguntado 3 anos atrás

AJUDA !!! POR FAVOR :) CONTINHA

Anexos:

Respostas

respondido por: thomazkostinskidev
1

Explicação passo a passo:

Item a:

a_6=a_1\cdot q^5\\\\a_6=64\cdot (\frac{1}{2})^5\\\\a_6=64\cdot\frac{1}{32}\\\\a_6=\frac{64}{32}\\\\a_6 = 2

Item b:

a_7=a_1\cdot q^6\\\\a_7=1\cdot (\sqrt{2})^6\\\\a_7=1\cdot 2^3\\\\a_7=1\cdot 8\\\\a_7=8

Item c:

a_8=a_1\cdot q^7\\\\a_8=16\cdot (-\frac{1}{2})^7\\\\a_8=16\cdot (-\frac{1}{128})\\\\a_8=-\frac{16}{128}\\\\a_8=-\frac{1}{8}

Item d:

a_7=a_1\cdot q^6\\\\a_7=(-81)\cdot(\frac{1}{3})^6\\\\a_7=(-81)\cdot\frac{1}{729}\\\\a_7=-\frac{81}{729}\\\\a_7=-\frac{1}{9}


lailicaperoncita: muito obrigadoo
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