Question

multiplicação com radicais
$10 \sqrt{2.} \sqrt{8}$
$\sqrt{2} . \sqrt{6} . \sqrt{3}$
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Answer 1

Explicação passo-a-passo:

$10 \sqrt{2} \times \sqrt{8}$

$10 \sqrt{2} \times \sqrt{2 {}^{3} }$

$10 \sqrt{2} \times \sqrt{2 {}^{2 + 1} }$

$10 \sqrt{2} \times \sqrt{2 {}^{2} \times 2 {}^{1} }$

$10 \sqrt{2} \times \sqrt{2 {}^{2} \times 2 }$

$10 \sqrt{2} \times \sqrt{2 {}^{2} } \sqrt{2}$

$10 \sqrt{2} \times 2 \sqrt{2}$

$10×2 \sqrt{2 \times 2}$

$20 \sqrt{4}$

$20 \times 2$

$40$

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$\sqrt{2} \times \sqrt{6} \times \sqrt{3}$

$\sqrt{2 \times 6 \times 3}$

$\sqrt{12 \times 3}$

$\sqrt{36}$

$\sqrt{6 {}^{2} }$

$6$