Question

⚠️ ME AJUDEM ESTOU DESESPERADO ⚠️


RESOLVA AS SEGUINTES ADIÇÕES E SUBTRAÇÕES SIMPLIFICANDO O RESULTADO QUANDO FOR NECESSÁRIO

Answer 1

a) $\frac{15}{9} - \frac{3}{9} = \frac{15-3}{9} = \frac{12}{9} = \frac{4}{3} = 1\frac{1}{3}$

b)$1\frac{1}{4} +2\frac{2}{4} + 1\frac{2}{4} =\frac{5}{4} +\frac{10}{4} +\frac{6}{4} = \frac{21}{4} = 5\frac{1}{4}$

c)$\frac{4}{6} + \frac{2}{5} = \frac{4x5}{6x5} + \frac{2x6}{5x6} = \frac{20}{30} + \frac{12}{30} = \frac{20+12}{30} = \frac{32}{30} = \frac{16}{15} = 1\frac{1}{15}$

d)$\frac{3}{4} + \frac{4}{6} = \frac{3}{4} + \frac{2}{3} =\frac{3x3}{4x3} + \frac{2x4}{3x4} =\frac{9}{12} + \frac{8}{12} = \frac{9+8}{12} = \frac{17}{12} = 1\frac{5}{12}$

e)$\frac{7}{4} - \frac{3}{2} + \frac{6}{8} = \frac{7}{4} + \frac{3}{4} - \frac{3}{2} = \frac{10}{4} - \frac{3}{2} = \frac{10}{4} - \frac{6}{4} = \frac{10-6}{4} =\frac{4}{4} = 1$

f)$1\frac{4}{6} - 1\frac{2}{3} = \frac{10}{6} - \frac{5}{3} = \frac{5}{3}-\frac{5}{3} = 0$