Question

AS RAIZES DA EQUAÇÃO -X² + X + 6 = 0 ??

Answer 1

-x² + x + 6 = 0
Δ = 1² - 4 .(-1).6
Δ = 1 + 24
Δ = 25

$x= \frac{- 1 +- \sqrt{25} }{2.(-1)} \\ \\ x= \frac{-1+-5}{-2} \\ \\ x^{1} = \frac{-1+5}{-2}= \frac{4}{-2}=-2 \\ \\ x^{2} = \frac{-1-5}{-2}= \frac{-6}{-2}=3$

S{-2,3}

Answer 2

- $x^{2}$ + x + 6 = 0 .(-1)
$x^{2}$ - x - 6 = 0

Δ = $b^{2}$ - 4.a.c
Δ = 1 + 24
Δ = 25

X' = - b + $\sqrt{Δ}$ /2.a         X'' = - b - $\sqrt{Δ}$ / 2.a

X' = - (-1) + 5 / 2 = 3                            X'' = - (-1) - 5 / 2 = - 2