Question

kokua!


gente ajudem porfavor resposta com cálculo! ñ é de marcar!


honi&mahalo!​

Answer 1

$a)$

2√3(√12 + √3)

2√3(√12)+2√3(√3)

2√36+2√9

2.6+2.3

12+6

= 18

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$b)$

(2+√3)(3-√3)

2(3)+2(-√3)+√3(3)+√3(-√3)

6-2√3+3√3-√9

6+√3-3

= 3+√3

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$c)$

(√2+√3) (2 - 2√3)

√2(2)+√2(-2√3)+√3(2)+√3(-2√3)

2√2-2√6+2√3-6

2√2-2√6+2√3-2√9

= 2√2-2√6+2√3-2.3

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$d)$

(2√5 + √7) (√5 - 2√7)

2√5(√5)+2√5(-2√7)+√7(√5)+√7(-2√7)

2√25-4√35+√35-2√49

2.5-3√35-2.7

10-3√35-14

= -4-3√35

Answer 2

Explicação passo-a-passo:

$a)2 \sqrt{3} .( \sqrt{12} + \sqrt{3} ) = 2 \sqrt{3.12} + 2 \sqrt{3.3} = 2 \sqrt{36} + 2 \sqrt{9} = 2 \times 6 + 2 \times 3 = 12 + 6 = 18$

$b)(2 + \sqrt{3} ).(3 - \sqrt{3} ) = 2.3 - 2 \sqrt{3} + 3 \sqrt{3} - ( \sqrt{3} ) {}^{2} =$

$6 - 2 \sqrt{3} + 3 \sqrt{3} - 3 = 3 + \sqrt{3} [/7tex]</p><p></p><p>[tex](2 \sqrt{5} + \sqrt{7} ).( \sqrt{5} - 2 \sqrt{7} ) = 2( \sqrt{5} ) {}^{2} - 4 \sqrt{35} + 7 \sqrt{35} - 2( \sqrt{7} ) {}^{2} = 10 + 11 \sqrt{35} - 14 =$

$11 \sqrt{35} - 4$

$( \sqrt{2} + \sqrt{3} ).(2 - \sqrt{3} ) = 2 \sqrt{2} - \sqrt{6} - 3 =$