• Matéria: Matemática
  • Autor: pedrodias1741
  • Perguntado 3 anos atrás

RESOLVA AS SEGUINTES EXPRESSÕES NUMERICAS
2. { 23+4.{ 200 . 18 - 5 . ( 9 . 70 - 3 . 40 ) } } =

Respostas

respondido por: rafaellemos937
0

Resposta: a=126(pode fazer direto)

b=-34(direto tbm)

c=0,81...x 24

19,44

d=25,5-6*-100

1659,5

e=1,9375-2,04

-0,1025

f=73*74

5402

g=25:5+8

5+8

13

h=(9+1)+10-10

10

i=9:3+3 x 4

2+12

14

j=70-[5 x 2+9]

70-19

61

k=11 x 9-8

11 x 1

11

l=25+8-2 x 12

31 x 12

372

m=36 ; 9+40-12

4+28

32

n=(49-1):5*5

48/25

1,92

o=16-10+(8-5)

16-10+3

6+3

9

p=30-(4+1)+8

30-5+8

25+8

32

q=30+[6^2/2+1]

30+[36/3]

30+12

42

r=20-[6-4*(10-9)+1]

20-[6-4*1+1]

20-[2*2]

20-4

16

s=50+[3^3/3+4*3]

50+[18/7*3]

50+[18/21]

50+0,8571...

50,8571

t=100-[5^2/5+12*1]

100-[25/17*1]

100-1,4705...

98,5295

u=[4^2+(125-12)]/(729-343)

[4^2+113]/386

[16+113]/386

129/386

0,3341

v=7^2+2*[(9+1)-4*1^3]

7^2+2*[10-4*1^3]

7^2+2*[6*1^3]

7^2+2*[6*1]

7^2+2*6

7^2+12

49+12

61

w=25+{3^3/9+[3^2*5-3*(8-5)]}

25+{3^3/9+[3^2*5-3*3]}

25+{3^3/9+[9*2*3]}

25+{3^3/9+54}

25+{12/9+54}

25+{1,333+54}

25+55,333

80,333

x=[(16+2*9)+(256/64)-35]^2+1^10-10^0

[162+4-35]^2+1^10-10^0

[26244+16-1225]

25035

y=4*4+{[9-8*12-5]*4}

4*4+{92*4}

4*4+368

16+368

384

z=25+{27/9+[9*5-3*(8-5)]}

25+{27/9+[9*5-3*3]}

25+{27/9+36}

25+39

64

Explicação passo-a-passo:esse * e vezes ok e / e dividir


rafaellemos937: Da aí a resposta
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