Question

PRECISO DO VALOR DO X PARA HOJEEEE

(√32)^x =1/128


(81/16)^x+1 = (3/2)^x-5

Answer 1

Resposta:

Explicação passo a passo:

$(\sqrt{32}) ^{x} =\frac{1}{128}$

$(\sqrt{2^{5} }) ^{x} =\frac{1}{2^{7} }$

$(2^{\frac{5}{2} }) ^{x} =2^{-7}$

$2^{\frac{5x}{2} }=2^{-7}$

 $\frac{5x}{2} =-7$

 $5x=-14$

  $x=-\frac{14}{5}$

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$(\frac{81}{16}) ^{x+1} =(\frac{3}{2}) ^{x-5}$

$[(\frac{3}{2}) ^{4}] ^{x+1} =(\frac{3}{2}) ^{x-5}$

$(\frac{3}{2}) ^{4x+4} =(\frac{3}{2}) ^{x-5}$

$4x+4=x-5$

$4x-x=-5-4$

     $3x=-9$

       $x=-\frac{9}{3}$

       $x=-3$