Question

Encontre a soma dos 100 primeiros termos da progressão aritmética ( 110 , 120 ,130 ,...).​

Answer 1

Resposta:

60.500

Explicação passo a passo:

r = 120 - 110 = 10

$a_1_0_0=a_1+99r\\\\a_1_0_0=110+99.10\\\\a_1_0_0=110 +990\\\\a_1_0_0=1100\\\\S_1_0_0=\frac{(110+1100).100}{2} \\\\S_1_0_0=1210.50\\\\S_1_0_0=60.500$