• Matéria: Matemática
  • Autor: Ritinhapaes
  • Perguntado 9 anos atrás

A integral de f(x)=sqrt(x)(x+1/x) é:

Respostas

respondido por: andresccp
2
\int \sqrt{x}\;(x+ \frac{1}{x} ) dx\\\\ \int (x*\sqrt{x}+ \frac{\sqrt{x}}{x} ) dx\\\\  \int (x*x^{ \frac{1}{2}} + \frac{x^{ \frac{1}{2} }}{x} )dx\\\\ \int (x^{1+ \frac{1}{2} }+x^{ \frac{1}{2}-1 })dx\\\\  \int (x^{ \frac{3}{2} }+ x^\frac{-1}{2})dx =   \frac{x^{ \frac{5}{2} }}{ \frac{5}{2} }  +  \frac{x^{ \frac{1}{2} } }{\frac{1}{2}} +C=  \boxed{\boxed{\frac{2x^{ \frac{5}{2} }}{5}+ 2x^{ \frac{1}{2} }+C}}
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