Question

10 qüestão por favor alguém mim explica

Answer 1

$a)\ \sqrt{50} + \sqrt{18} - \sqrt{8} \\ = \sqrt{25\cdot2} + \sqrt{9\cdot2} - \sqrt{4\cdot2} \\ = \sqrt{25}\cdot\sqrt{2} + \sqrt{9}\cdot\sqrt{2} - \sqrt{4}\cdot\sqrt{2} \\ = 5\sqrt{2} + 3\sqrt{2} -2\sqrt{2} \\ = 6 \sqrt{2}$
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$b)\ 4\sqrt{63} + \sqrt{7} \\ = 4\sqrt{9\cdot7} + \sqrt{7} \\ = 4\sqrt{9}\cdot\sqrt{7} + \sqrt{7} \\ = 4\cdot3\cdot\sqrt{7} + \sqrt{7} \\ = 12\sqrt{7} + \sqrt{7} \\ = 13 \sqrt{7}$
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$c)\ 5\sqrt[5]{3} +2\sqrt[5]{3} -2\sqrt[5]{3}+\sqrt[5]{3} \\ = 6\sqrt[5]{3}$
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$d)\ 2\sqrt{27} - 5 \sqrt{12} \\ =2\sqrt{9\cdot 3} - 5 \sqrt{4\cdot 3} \\ =2\sqrt{9} \cdot \sqrt{3} - 5 \sqrt{4}\cdot \sqrt{3} \\ =2\cdot3 \cdot \sqrt{3} - 5 \cdot2\cdot \sqrt{3} \\ =6 \sqrt{3} - 10 \sqrt{3} \\ =-4 \sqrt{3}$
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$e)\ \sqrt{12} + \sqrt{75}+ \sqrt{108} \\ = \sqrt{4\cdot3} + \sqrt{25\cdot 3}+ \sqrt{36\cdot3} \\ = \sqrt{4}\cdot\sqrt{3} + \sqrt{25}\cdot \sqrt{3}+ \sqrt{36}\cdot\sqrt{3} \\ = 2\sqrt{3} + 5 \sqrt{3}+ 6\sqrt{3} \\ = 13\sqrt{3}$