Dados os vetores .....
Anexos:
Anônimo:
Pessoal eu so preciso da pergunta 10 nao to conseguindo faze
Respostas
respondido por:
1
Boa tarde Renata!
Solução!
Para resolver esse exercicio,precisa montar um sistema linear com os vetotores.
Vou chamar de:
a1=a
a2=b
![Sendo\\\\\
\vec{u}=(3,8)\\\\
\vec{v}=(2,-2)\\\\
\vec{w}=(-5,-6)](https://tex.z-dn.net/?f=Sendo%5C%5C%5C%5C%5C%0A%5Cvec%7Bu%7D%3D%283%2C8%29%5C%5C%5C%5C%0A%5Cvec%7Bv%7D%3D%282%2C-2%29%5C%5C%5C%5C%0A%5Cvec%7Bw%7D%3D%28-5%2C-6%29 "Sendo\\\\\
\vec{u}=(3,8)\\\\
\vec{v}=(2,-2)\\\\
\vec{w}=(-5,-6)")
Montando o sistema com os vetores:
![a(\vec{u})-b(\vec{v})=\vec{w}\\\\\
a(3,8)-b(2,-2)=(-5,-6)\\\\\
3a-2b=-5\\
8a+2b=-6\\\\\
8a+3a=-6-5\\\\
11a=-11\\\\
a= \frac{-11}{11}\\\\
a=-1\\\\\\
Calculo~~de~~b\\\\\\
3a-2b=-5\\\\
3(-1)-2b=-5\\\\
-3-2b=-5\\\\
-2b=-5+3\\\\
-2b=-2\\\\
b= \dfrac{-2}{-2} \\\\
b=1](https://tex.z-dn.net/?f=a%28%5Cvec%7Bu%7D%29-b%28%5Cvec%7Bv%7D%29%3D%5Cvec%7Bw%7D%5C%5C%5C%5C%5C%0Aa%283%2C8%29-b%282%2C-2%29%3D%28-5%2C-6%29%5C%5C%5C%5C%5C%0A3a-2b%3D-5%5C%5C%0A8a%2B2b%3D-6%5C%5C%5C%5C%5C%0A8a%2B3a%3D-6-5%5C%5C%5C%5C%0A11a%3D-11%5C%5C%5C%5C%0Aa%3D+%5Cfrac%7B-11%7D%7B11%7D%5C%5C%5C%5C%0Aa%3D-1%5C%5C%5C%5C%5C%5C%0ACalculo%7E%7Ede%7E%7Eb%5C%5C%5C%5C%5C%5C%0A+3a-2b%3D-5%5C%5C%5C%5C%0A3%28-1%29-2b%3D-5%5C%5C%5C%5C%0A-3-2b%3D-5%5C%5C%5C%5C%0A-2b%3D-5%2B3%5C%5C%5C%5C%0A-2b%3D-2%5C%5C%5C%5C%0Ab%3D+%5Cdfrac%7B-2%7D%7B-2%7D+%5C%5C%5C%5C%0Ab%3D1 "a(\vec{u})-b(\vec{v})=\vec{w}\\\\\
a(3,8)-b(2,-2)=(-5,-6)\\\\\
3a-2b=-5\\
8a+2b=-6\\\\\
8a+3a=-6-5\\\\
11a=-11\\\\
a= \frac{-11}{11}\\\\
a=-1\\\\\\
Calculo~~de~~b\\\\\\
3a-2b=-5\\\\
3(-1)-2b=-5\\\\
-3-2b=-5\\\\
-2b=-5+3\\\\
-2b=-2\\\\
b= \dfrac{-2}{-2} \\\\
b=1")
![Prova\\\\
-1(3,8)-1(2,-2)=(-5,-6)\\\\
(-3-2)=-5\\\
-5=-5\\\\\
(-8+2)=-6\\\
-6=-6](https://tex.z-dn.net/?f=Prova%5C%5C%5C%5C%0A-1%283%2C8%29-1%282%2C-2%29%3D%28-5%2C-6%29%5C%5C%5C%5C%0A%28-3-2%29%3D-5%5C%5C%5C%0A-5%3D-5%5C%5C%5C%5C%5C%0A%28-8%2B2%29%3D-6%5C%5C%5C%0A-6%3D-6 "Prova\\\\
-1(3,8)-1(2,-2)=(-5,-6)\\\\
(-3-2)=-5\\\
-5=-5\\\\\
(-8+2)=-6\\\
-6=-6")
Boa tarde!
Bons estudos!
Solução!
Para resolver esse exercicio,precisa montar um sistema linear com os vetotores.
Vou chamar de:
a1=a
a2=b
Montando o sistema com os vetores:
Boa tarde!
Bons estudos!
muito obrigado pode me ajudar nessa ? http://brainly.com.br/tarefa/4845658
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