• Matéria: Matemática
  • Autor: igorferreirajesus
  • Perguntado 3 anos atrás

Ajudinha prfvvvvvvvv

Anexos:

Respostas

respondido por: Anônimo
1

Explicação passo a passo:

\left[\begin{array}{ccc}m&2m\\p&p\\\end{array}\right] +\left[\begin{array}{ccc}n&-n\\q&-3q\\\end{array}\right] = \left[\begin{array}{ccc}7&8\\1&5\\\end{array}\right]

\left[\begin{array}{ccc}m+n&2m+(-n)\\p+q&p+(-3q)\\\end{array}\right] =\left[\begin{array}{ccc}7&8\\1&5\\\end{array}\right]

\left[\begin{array}{ccc}m+n&2m-n\\p+q&p-3q\\\end{array}\right] =\left[\begin{array}{ccc}7&8\\1&5\\\end{array}\right]

{m + n = 7

{2m - n = 8

-----------------

3m = 15

m = 15 / 3

m = 5

m + n = 7

5 + n = 7

n = 7 - 5

n = 2

{p + q = 1  (-1)

{p - 3q = 5

{-p - q = -1

{p - 3q = 5

--------------------

-4q = 4

q = - 4 / 4

q = -1

p + q = 1

p + (-1) = 1

p - 1 = 1

p = 1 + 1

p = 2

\left[\begin{array}{ccc}m&2m\\p&p\\\end{array}\right] +\left[\begin{array}{ccc}n&-n\\q&-3q\\\end{array}\right] = \left[\begin{array}{ccc}7&8\\1&5\\\end{array}\right]

\left[\begin{array}{ccc}5&2.5\\2&2\\\end{array}\right] +\left[\begin{array}{ccc}2&-2\\-1&-3.(-1)\\\end{array}\right] = \left[\begin{array}{ccc}7&8\\1&5\\\end{array}\right]

\left[\begin{array}{ccc}5&10\\2&2\\\end{array}\right] +\left[\begin{array}{ccc}2&-2\\-1&3\\\end{array}\right] = \left[\begin{array}{ccc}7&8\\1&5\\\end{array}\right]

Bons estudos da madrugada :D

Anexos:
Perguntas similares