Question

2) Considerando f: R → R, onde f(x) = x2 - 2x, determine:
a) f(2) = (2)2 - 2.(2) = 4 - 4 = 0 (exemplo)
b) f(-1) =
c) f(3) =
d) f(-2) =
e) f(0) =

Answer 1

Vamos là.

f(x) = x² - 2x

a) f(2) = 2² - 2*2 = 4 - 4 = 0

b) f(-1) = (-1)² - 2*(-1) = 1 + 2 = 3

c) f(3) = 3² - 2*3 = 9 - 6 = 3

d) f(-2) = (-2)² -2*(-2) = 4 + 4 = 8

e) f(0) = 0