Question

se a = (o,ooo1) ^-2 e b = (10^2)^3, calcule


a×b=

a/b=

b/a=​

Answer 1

$\boxed{\begin{array}{l}\sf a=(0,0001)^{-2}=(10^{-4})^{-2}=10^8\\\sf b=(10^2)^3=10^6\\\sf a\times b=10^8\times 10^6=10^{8+6}=10^{14}\\\sf\dfrac{a}{b}=\dfrac{10^8}{10^6}=10^{8-6}=10^2\\\\\sf\dfrac{b}{a}=\dfrac{10^6}{10^8}=10^{6-8}=10^{-2}\end{array}}$