Question

1.)Qual é o volume de água em litros de uma piscina que tem 15 metros de comprimento, 2 metros de profundidade e 4 metros de largura? 

a) 120L

b) 1200L

c) 12000L

d) 120.000L



2) 0,8 dam convertido em km², temos? 

a) 0,08 km²

b) 0,00008 km²

c) 0,8 km²

d) 8 km²



3.) Quantos metros temos em 0,08 hm²? 

a) 8 m²

b)0,8 m²

c) 80 m²

d) 800 m²

​

Answer 1

Resposta:

1 a 2 d 3 c

Explicação passo-a-passo:

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Answer 2

If the swimming pool has:

15m of length;

2m of height;

4m of width;

Thus, for it's volume $V$:

$V=\int{\int{\int\limits_R dV$

Where $R=[(x, y, z), 0\leq x\leq 15, 0\leq y\leq 4, 0\leq z\leq 2]$

Hence,

$V=\int{\int{\int\limits_R dV=\int\limits^{15}_0{\int\limits^4_0 {\int\limits^2_0\, dz } \, dy } \, dx$

$V=\int\limits^{15}_0 {\int\limits^4_0 {[z]^2_0 \, dy } \, dx$

$V=2\int\limits^{15}_0 {\int\limits^4_0\, dy } \, dx$

$V=2\int\limits^{15}_0 {[y]^4_0} \, dx$

$V=8\int\limits^{15}_0dx$

$V=8[x]^{15}_0$

$V=8$ × $15$

$V=120$

Therefore, the swimming pool has volume $V=120$L.

I have already done the first one. Try doing the other ones by yourself, otherwise, you're not going to learn.

Hope I've helped, enjoy your studies.