• Matéria: Matemática
  • Autor: Uhanan
  • Perguntado 3 anos atrás

Como resolver

Tg²x-1=0

Respostas

respondido por: CyberKirito
1

\Large\boxed{\begin{array}{l}\sf tg^2x-1=0\\\sf tg^2x=1\\\sf tg\,x=\pm\sqrt{1}\\\sf tg\,x=\pm1\\\sf tg\,x=1\\\sf\iff x=\dfrac{\pi}{4}+k\pi~ou~x=\dfrac{5\pi}{4}+k\pi,k\in\mathbb{Z}\\\\\sf tg(x)=-1\\\sf\iff x=\dfrac{3\pi}{4}+k\pi~ou~x=\dfrac{7\pi}{4}+k\pi,k\in\mathbb{Z}\end{array}}

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