Question

(EFEI-MG) Encontre a matriz A = (aij)2x2 tal que A = [i² 2i] [-j 2j ]

Answer 1

a11 =  [1² * 2*1] [-1*2*1] = 2*-2 = -4

a12 = [1² * 2*1] [-2*2*2] = 2*-8 = -16

a21 = [2² * 2*1] [-1*2*1] = 8*-2 = -16

a22 = [2² * 2*2] [-2*2*2] = 16 *-8 = -128

M(2x2) = {(-4,-16) ; (-16,-128)}

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05/04/2016
Sepauto - SSRC
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