Question

resolva as seguintes equações do 2° grau,sendo U=R. ײ-6×+9=0

Answer 1

Use a fórmula de Bhaskara:

$\Delta=b^2-4ac\\ \Delta =(-6)^2-4.1.9=36-36=0\\ \\ x=\frac{-b}{2a}=\frac{6}{2}=3\\ \\ S=\{3\}$

Answer 2

x² - 6x + 9 = 0

Δ = b²−4ac
Δ = (−6)²−4⋅1⋅9
Δ = 36−36
Δ = 0

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$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\ x = \dfrac{-(-6) \pm \sqrt{0}}{2*1}\\ \\ \\ x = \dfrac{6 \pm 0}{2}\\ \\ \\x' = \dfrac{6 + 0}{2}\\ \\ \\x' = \dfrac{6}{2}\\ \\ \\x' = 3\\ \\ \\x' = \dfrac{6 - 0}{2}\\ \\ \\x' = \dfrac{6}{2}\\ \\ \\x' = 3$

S = {3}