• Matéria: Matemática
  • Autor: RobertaURREA12
  • Perguntado 3 anos atrás

Resolva as equações: a)60x+120+50=20x-80 b)4x/2+16=2x/3+40 c)18(x+20)-60=135+10x

por favor me ajudem é para entregar amanhã!!!!​

Respostas

respondido por: karol1981
1

Resposta:

60x+120+50=20x−80

60x+=20x-8060x+120+50=20x−80

60x+170=20x−80

60x+170=20x−80

60x+170=20x-8060x+170=20x−80

60x+170−170=20x−80−170

60 x=20 x−250

60=20−250

60x=20x-25060x=20x−250

60−20=20−250−20

40=−250

=−25 sob 4 (Resposta)

b)

42+16=23+40

+4024x​+16=32x​+40

2+16=23+40

2+16=23+40

2x+16=+402x+16=32x​+40

2+16=23+3⋅403

2+16=23+3⋅403

2x+16=2x+16=32x​+33⋅40​

2+16=2+3⋅403

2+16=2+3⋅403

2x+16=2x+16=32x+3⋅40​

2+16=2+1203

2+16=2+1203

2x+16=2x+16=32x+120​

2+16−16=2+1203−16

=18 (Resposta)

c)

18(+20)−60=135+10

-60=135+10x18(x+20)−60=135+10x

18+360−60=135+10

18+360−60=135+10

18x+=135+10x18x+360−60=135+10x

18+300=135+10

18+300=135+10

18x+300=18x+300=135+10x

18+300=10+135

18+300=10+135

18x+300=10x+13518x+300=10x+135

18+300−300=10+135−300

18=10−165

=−1658 (Resposta)


RobertaURREA12: muito obrigada♥️
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