Question

calcule o valor das potências a seguir: ​


me ajuda pfvr

Answer 1

$\bf\large{\underline{\qquad \qquad\qquad \qquad \qquad \qquad \qquad \quad }}$

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Resposta correta:

• ${~~~~\boxed{\boxed{\begin{array}{lr}\green{a)81}\end{array}}\boxed{\begin{array}{lr}\green{b) \frac{49}{9} }\end{array}}\boxed{\begin{array}{lr}\green{c)125}\end{array}}\boxed{\begin{array}{lr}\green{d)256}\end{array}}\boxed{\begin{array}{lr}\green{e)9}\end{array}}\boxed{\begin{array}{lr}\green{f )-125}\end{array}}}}$

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$\underline{\underline{\overline{\overline{\begin{gathered}\boxed{\begin{array}{l} \\\sf\begin{gathered}\large\textsf{\textbf{\underline{Calculo:}}}\end{gathered} \\\ ~ \\\ \large a)~3^{4}= 3\times3\times3\times3=81 \\\ \\\ \large b)~(\frac{7}{3})^{2}=\frac{7^{2}}{3^{2}}=\frac{49}{9}\\\ \\\ \large c)~5^{3}=5\times5\times5=125\\\ \\\ \large d)~(-4)^{4}=4^{4}=4\times4\times4\times4=256\\\ \\\ \large e)~(-3)^{2}=3^{2}=3\times3=9\\\ \\\ \large f)~(-5)^{3}=-5^{3}=-(5\times5\times5)=-125 \\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\end{array}}\end{gathered}}}}}$

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$~~~~~~~~~~~\bf Att.$

${\Huge{\underline{\green{\mathbb{P}}E\green{\mathbb{R}}G\green{\mathbb{U}}N}}} \\ { \Huge{ \: \: \: \: \: \: \: \: \: \: \: \: {{\underline{\green{ T}\mathbb{A}\green{D}\mathbb{O}\green{S}}}}}}$

$\bf\large{\underline{\qquad \qquad\qquad \qquad \qquad \qquad \qquad \quad }}$

Answer 2

a) 3⁴ = 3 x 3 x 3 x 3 = 81

b) 7/3² = 7 x 7/ 3 x 3 = 49/9

c) 5³ = 5 x 5 x 5 = 125

d) (-4)⁴ = -4 x -4 x -4 x -4 = 256

e) (-3)² = -3 x -3 = 9

f) (-5)³ = -5 x -5 x -5 = -125

OBS.: OS NÚMEROS NEGATIVOS COM EXPOENTES ÍMPARES: RESULTADOS NEGATIVOS E COM EXPOENTES PARES: RESULTADOS POSITIVOS.