Question

determine o ponto medio do segmento de extremidades: a) A(1,-7) e B(3,-5) b)A(-1,5) eB (5,-2) c)A (-4,-2) eB (-2,-4) d)A(-1,0) e B(0,-2)

Answer 1

Ponto médio dos pontos A e B, mAB,  é dado por M(mx,my) onde:

mx = (xA+ xB/2

my = (yA +yB)/2

a) M(AB) =  (2,-6) 
   
b) M(AB) = (2; 3/2)

c) M(AB) = (-3,-3)

d) M(AB) = (-1/2,-1)

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05/04/2016
Sepauto - SSRC
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Answer 2

Boa noite!

Solução!
Para determinar o ponto médio de um seguimento vamos usar essa formula.

$M=\left ( \dfrac{xa+xb}{2}, \dfrac{ya+yb}{2} \right )$


$a) A(1,-7) ~~e~~ B(3,-5)\\\\\ M=\left ( \dfrac{1+3}{2}, \dfrac{-7-5}{2} \right )\\\\\\\\ M=\left ( \dfrac{4}{2}, \dfrac{-12}{2} \right )\\\\\\\\\\ M=\left ( 2, -6\right )$

$b)A~~(-1,5) ~~e~~B (5,-2) \\\\\\\\ M=\left ( \dfrac{-1+5}{2}, \dfrac{5-2}{2} \right )\\\\\\\ M=\left ( \dfrac{4}{2}, \dfrac{3}{2} \right )\\\\\\\\\\ M=\left ( 2, \dfrac{3}{2} \right )$


$c)~~A (-4,-2)~~ e~~B (-2,-4)~\\\\\\\ M=\left ( \dfrac{-4-2}{2}, \dfrac{-2-4}{2} \right )\\\\\\\ M=\left ( \dfrac{-6}{2}, \dfrac{-6}{2} \right )\\\\\\\ M=\left ( -3,-3 \right )$


$d)~~A(-1,0) ~~e ~~B(0,-2)\\\\\\ M=\left ( \dfrac{-1+0}{2}, \dfrac{-2+0}{2} \right )\\\\\\\ M=\left ( \dfrac{-1}{2}, \dfrac{-2}{2} \right )\\\\\\\ M=\left ( \dfrac{-1}{2}, -1\right )$

Boa noite!
Bons estudos!