Question

resolva
a) 2x²-7x=0
b) -3x²+4x=0
c) -x²+x=0
d) 4x²+2x=0​

Answer 1

Resposta:

Explicação passo a passo:

a) 2x²-7x=0 => x(2x - 7 ) = 0 => x= 0=>  $x_{1}= 0$ =>  x2 = 2x = 7  =>   $x_{2}= \frac{7}{2}$

b) -3x²+4x=0=> x(-3x + 4) = 0 =>  $x = 0 => x_{1}= 0 \\-3x + 4 = 0 => -3x = -4(-1) => 3x = 4 => x_{2} = \frac{4}{3}$  

c) -x²+x=0 => x(-x +1) =0 => $x = 0 => x_{1}= 0 \\-x + 1 = 0 => -x = -1(-1) => x = 1 => x_{2} = 1$

d) 4x²+2x=0​ => 2x(2x + 1) = 0 => $2x = 0 => x =\frac{0}{2} => x_{1}= 0 \\2x + 1 = 0 => 2x = -1 => x_{2} = -\frac{1}{2}$