Question

Derive


10$\sqrt[3]{x^{2} +3x}$

Answer 1

$y =10  \sqrt[3]{x^2+3x} \\ \\ y=10(x^2+3x) ^{ \frac{1}{3} } \\ \\ y'= 10\frac{1}{3} (x^2+3x) ^{ \frac{1}{3}-1 }(x^2+3x)' \\ \\ y'=\frac{10}{3} (x^2+3x) ^{- \frac{2}{3} } (2x+3)$

Se quiser pode continuar.