Question

b) 20º termo da PA (6,25/4,13/2 , … )​

Coloca a conta ​

Answer 1

$\large O ~valor ~do ~vig\acute{e}simo ~termo ~da ~PA ~ \Rightarrow ~ a20 = \dfrac{43}{4}$

                                     $\Large Progress\tilde{a}o ~Aritm\acute{e}tica$

Encontrar a razão da PA:

$r = a2 - a1\\\\\\r = \dfrac{25}{4} - 6\\\\\\r =\dfrac{1}{4}$

Encontrar o valor do termo a20:

$an = a1 + ( n -1 ) . r\\\\\\a20 = 6 + ( 20 -1 ) . \dfrac{1}{4}\\\\\\a20 = 6 + 19 . \dfrac{25}{4}\\\\\\a20 = 6 + \dfrac{19}{4}\\\\\\a20 = \dfrac{43}{4}$

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