Question

1) Resolva as equações exponenciais:​

Answer 1

Resposta:

Oi!

$2^{2x+1} = 2^3\\2x + 1 = 3\\2x = 3 - 1\\2x = 2\\x = 2/2\\x= 1\\\\\\3^{2(-3x-2)} = 3^{3(2x+1)}\\2(-3x-2) = 3(2x+1)\\-6x - 4 = 6x + 3\\-6x-6x = 3 + 7\\-12x = 10\\x = \frac{10}{-12} \\x = -\frac{5}{6} \\\\\\\\5^{2(x+4)} = 5^{3(3x+2)}\\2x + 8 = 9x + 6\\7x = 2\\x = \frac{2}{7} \\\\\\4^{2x+3} = 4^{3(x-8)}\\2x + 3 = 3x - 24\\2x - 3x = -24 - 3\\-x = -27\\x = 27$

Explicação passo a passo: