Question

Simplifique as raízes:

a)√12

b)√48
c)∜80
d)∛729

Answer 1

Resposta:

$Simplifique \ os \ radicais:\\\\a)\sqrt{12} =\sqrt{2^2 \ . \ 3} =\sqrt{2^2} \sqrt{3} =2\sqrt{3} \\\\b)\sqrt{48} =\sqrt{2^4 \ . \ 3} =\sqrt{2^4} \sqrt{3} =4\sqrt{3} \\\\c)\sqrt[4]{80} =\sqrt[4]{2^4 \ . \ 5} =\sqrt[4]{2^4} \sqrt[4]{5} =2\sqrt[4]{5} \\\\d)\sqrt[3]{729} =\sqrt[3]{9^3} =9$