• Matéria: Matemática
  • Autor: danieloliveirav97
  • Perguntado 3 anos atrás

adição de fraçao com denominadores diferentes ​

Anexos:

Respostas

respondido por: CyberKirito
1

\Large\boxed{\begin{array}{l}\underline{\rm m\acute etodo\,da\,borboleta}\\\sf\dfrac{2}{7}+\dfrac{6}{6}=\dfrac{2\cdot6+7\cdot6}{7\cdot6}=\dfrac{9\cdot\backslash\!\!\!6}{7\cdot\backslash\!\!\!6}=\dfrac{9}{7}\\\\\sf \dfrac{2}{5}+\dfrac{3}{8}=\dfrac{2\cdot8+5\cdot3}{5\cdot8}=\dfrac{16+15}{40}=\dfrac{31}{40}\\\\\sf\dfrac{1}{3}+\dfrac{3}{6}=\dfrac{1\cdot6+3\cdot3}{3\cdot6}=\dfrac{6+27}{18}\\\\\sf\dfrac{1}{3}+\dfrac{3}{6}=\dfrac{33\div3}{18\div3}=\dfrac{11}{9}\end{array}}

Anexos:
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