• Matéria: Matemática
  • Autor: millenasilva2106
  • Perguntado 3 anos atrás

1) resolva as seguintes equações:

a) 3 × + 5 = 19

b) 2 × + 1 = 21

c) 3 × + 5 = 2 × - 2

d) 4 × + 3 = 2 × + 13 ​

Respostas

respondido por: Anônimo
1

Resposta:

a)3x+5=19\\\\3x+5-5=0\\\\3x=19-5\\\\3x=14\\\\x=\frac{14}{3} \\

b)2x+1=21\\\\2x+1-1=0\\\\2x=21-1\\\\2x=20\\\\x=20:2\\\\x=10

c)3x+5=2x-2\\\\3x+5-5=0\\\\3x=2x-2-5\\\\3x=2x-7\\\\3x-2x=7-2x\\\\x= -7

d)4x+3=2+13\\\\4x+3-3=0\\\\4x=2x+13-3\\\\4x=2x+10\\\\4x-2x=10-2x\\\\2x=10\\\\x=10:2\\\\x=5

respondido por: eduardoaltorizadoalt
1

Explicação passo-a-passo:

3x + 5 = 19 \\  3x = 19 - 5 \\ 3x = 14 \\ x =  \frac{14}{3}

2x + 1 = 21 \\ 2x = 21 - 1 \\ 2x = 20 \\ x = 10

3x + 5 = 2x - 2 \\ 3x + 5 - 2x =  - 2 \\ 3x - 2x =  - 2 - 5 \\ x =  - 2 - 5 \\ x =  - 7

4x + 3 = 2x + 13 \\ 4x + 3 - 2x = 13 \\ 4x - 2x = 13 - 3 \\ 2x = 13 - 3 \\ 2x = 10 \\ x = 5

bons estudos

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